JEE Main Percentile Calculator
The All India Rank your JEE Main percentile points to, and a percentile from your shift's candidate counts by NTA's own formula.
Unique candidates of 2026, from NTA's result notice
53,847
About 53,846 of 15,38,468 candidates ahead, at an NTA score of 96.5000000.
An estimate: NTA publishes no percentile-to-rank conversion.
Working
JEE (Main) results are given as percentiles, which NTA calls NTA scores. This calculator estimates the All India Rank your percentile points to, and works out a percentile from your shift's counts by the normalisation formula in the 2026 Information Bulletin, rounded to 7 decimal places as NTA does, with each step.
A percentile needs counts that only NTA has before results: how many candidates appeared in your shift and how many scored the same as you or less. Marks alone do not give a percentile, which is why the calculator asks for counts and does not convert marks.
How to use it
Rank from percentile takes your percentile from Session 1, Session 2 or both, and the candidates across both sessions, set to the 15,38,468 unique candidates who appeared for Paper 1 in 2026. With two percentiles, the better one counts. A percentile given to more than 7 decimal places is rounded to 7.
Percentile from counts takes the candidates who appeared in your shift and the candidates whose total raw score is equal to or less than yours, you included. Subject percentiles follow the same formula with each subject's raw score.
How NTA normalises scores
JEE (Main) runs over several days in two shifts a day, with a different paper in each shift. However carefully papers are matched, one shift can be harder than another, so raw marks are not compared across shifts. Each candidate's raw score is instead turned into a percentile within their own shift: the percentage of that shift's candidates who scored the same or less.
The highest scorer in every shift is at or above everyone in it, so every shift's topper gets 100, whatever their marks. The lowest score gets 100 × its count ÷ the shift's candidates, which is small but never 0. The total percentile comes from the total raw score; it is not an average of the subject percentiles.
The rank estimate assumes the merged NTA scores are spread evenly: a percentile of P leaves about (100 − P)% of all candidates ahead. NTA defines no such conversion, ties at one NTA score are ordered by the tie-break rules below, and candidates who took both sessions keep only their better score, so the merged list leans toward the top. Treat the result as a rough guide to the size of the rank.
Percentile = 100 × candidates in the shift with a raw score equal to or less than yours ÷ candidates who appeared in the shift
Estimated rank ≈ candidates × (100 − percentile) ÷ 100 + 1
Examples
The bulletin's candidate B
In the bulletin's example shift, 41,326 candidates appeared and 37,244 scored 121 or less. With those two counts under Percentile from counts, the percentile is 90.1224411, the figure the bulletin prints:
- Percentile = 100 × candidates in the shift with a total raw score equal to or less than yours ÷ candidates who appeared in the shift. 100 × 37,244 ÷ 41,326 = 90.1224410782…
- Round to 7 decimal places. 90.1224411
A negative raw score
Candidate E in the same shift scored −15, and 456 candidates scored that or less. The percentile is 1.1034216: a negative raw score still has a positive percentile, because the count includes the candidate.
A rank estimate
A Session 1 percentile of 96.5, with Session 2 left empty and the 15,38,468 candidates of 2026, puts about 53,846 candidates ahead, for an estimated rank of 53,847:
- Candidates ahead ≈ candidates × (100 − your percentile) ÷ 100, to the nearest whole candidate. 15,38,468 × (100 − 96.5000000) ÷ 100 = 53,846.38 ≈ 53,846
- Estimated rank = candidates ahead + 1. 53,846 + 1 = 53,847
JEE (Advanced) 2026 cut-offs
| Category | Lowest NTA score | Candidates eligible |
|---|---|---|
| General (UR) | 93.4123549 | 96,873 |
| EWS | 82.4164528 | 25,009 |
| OBC-NCL | 80.9232583 | 67,597 |
| SC | 63.9172792 | 37,522 |
| ST | 52.0174712 | 18,790 |
| General PwBD | 0.0023186 | 4,391 |
NTA's rules
Percentiles are calculated shift by shift to 7 decimal places, and the percentiles of every shift of both sessions are merged into one merit list. A candidate who sat both sessions keeps the better of their two total NTA scores, not the better score in each subject.
When the qualifying marks for a category fall at different percentiles in different shifts, the lowest of those percentiles becomes the cut-off for every shift.
Candidates with the same total NTA score are ordered by, in turn:
- the NTA score in Mathematics;
- the NTA score in Physics;
- the NTA score in Chemistry;
- the lower ratio of incorrect to correct answers across all subjects;
- the same ratio in Mathematics;
- the same ratio in Physics;
- the same ratio in Chemistry;
- and if still tied, the same rank.
Sources
- JEE (Main) 2026 Information Bulletin, Appendix-VII: Normalization procedure based on Percentile Score (pp. 55–58) — National Testing Agency
- Declaration of the Result/NTA Scores for JEE (Main) 2026 Paper 1 (B.E./B.Tech.), press release of 20 April 2026 — National Testing Agency
Reviewed
Frequently asked questions
See also
- Percentile Calculator — for any percentile of a data set, or a score's percentile rank by the at-or-below and mid-rank definitions.
- Percentage Calculator — to work out a percentage of marks, which is a different figure.